WebStandard household foil is typically 0.016 mm thick. The foil is 1.6*10^-5 m thick The diameter of the Al atom is 2.86*10^–10 m Number of Al atoms making up the thickness of the Al foil = Atoms = (1.6*10^-5 m) ÷ ( 2.86*10^-10 m) = 55,944 at Continue Reading More answers below Tanya Pizzolatto 1 y Insufficient information.

Compute the thickness of the foil in number of atoms given the

WebThe thickness of aluminum foil is about 0.002 cm. A mole of aluminum weighs 27 grams The density of aluminum is 2.7 grams per cubic cm So one mole occupies a cube with volume of 10 cc. Or 1 cc contains 0.1 mols or 6.02E22 atoms. The cube root gives 3.92E7 atoms/cm on a side Multiply this by the thickness of the foil gives ~75,000 atoms thick WebThink about how you would calculate the volume of a box from its measurement. Think of the piece of aluminum foil as a very thin box.) You calculated the volume of the foil in analysis #2. Using the formula V = l x w x h… solve for h. One aluminum atom has a diameter of 0.000000025 cm. How many atoms thick is the aluminum foil? trading company distributor wholesaler

Determining the Thickness of Aluminum Foil - Anoka-Hennepin …

WebDetermining the Thickness of Aluminum Foil. By dividing the mass by a known density value, we obtained the volume of aluminum foil in our sample. By dividing that by the surface area, we found the thickness of the aluminum foil in cm. (The value was 2.86 *10^-3 cm.) The value converted to be 2.86*10^5 angstroms. WebHomework help starts here! Science Chemistry Determine the thickness of an aluminum foil in atoms with the following information: Weight: 0.633 g Volume: 0.301 cm^3 Length: 13.3 mm Width: 10.5 mm Al Atomic Radius: 1.82 Å Al Density: 2.70 g/cm3 1 Å = 1x10-10m. WebAluminum foil is .003 cm thick. Assume that all of the unit cells are arranged perpendicular to the foil surface. For a 10cm x 10cm spuare of the foil, determine: a. The total number … the salem playhouse